5th Maths Term 1 Unit 4 Measurements Exercise 4.1 (Length) Solutions

5th Maths: Term 1 Unit 4 Measurements - Exercise 4.1 (Length)

5th Maths : Term 1 Unit 4 : Measurements

Exercise 4.1 (Length)

Text Book Back Exercises Questions with Answers, Solution

1. Fill in the blanks

a. 7m 5cm = 705 cm
b. 505 mm = 50 cm 5 mm
c. 326 m = 32600 cm
d. 5km 30 m = 5030 m
e. 650 cm = 6 m 50 cm

2. True or False

a) 600 m is 6 mm. (False)
b) 7000 m is 7 km. (True)
c) 400 cm is 4 km. (False)
d) 770 mm is 77 cm. (True)
e) 9000 m is 90 mm (False)

3. Find the sum of the following.

a. 17m 450cm + 52m 300cm Sum calculation a Answer: 69 m 750cm
b. 75km 400m + 37km 300m + 52km 750m Sum calculation b Answer: 165km 450m
c. 4cm 8mm + 5cm 9mm Sum calculation c Answer: 10cm 7mm

4. Subtract the following

a. 15km 450m − 13km 200m. Subtraction calculation a Answer: 2Km 250m
b. 750m 840mm − 370m 480 mm Subtraction calculation b Answer 380m 360mm
c. 5km 400m − 3km 350m Subtraction calculation c Answer: 2Km 050m

5. Multiply the following.

a. 350m 45cm × 7 Answer = 2453m 15cm
b. 25km 300m × 6 Answer = 151km 800m
c. 37m 350mm × 8 Answer = 298 in 800mm

6. Divide the following:

a. 950km 800m ÷ 5 Division calculation a Answer: 190 km 160 m
b. 49m 770mm ÷ 7 Division calculation b Answer: 7 m 110m
c. 172m 48cm ÷ 4 Division calculation c Answer: 43 m 12 cm

LIFE ORIENTED PROBLEMS

7. Answer the following:

a. Saravanan had chosen to drive his vehicle from puducherry to Chennai for a distance of 165 Kms. While starting his vehicle, his odometer showed 00015. What will be the reading of the odometer, When he reaches Chennai?
The reading of the odometer at the starting = 00015km +
Distance travelled = 165km
When he reaches Chennai the reading of the Odometer = 00180km
b. Karthik Raja decided to travel from A. He moves 1Km east to reach B. Then he goes 2 Km towards north and reaches C. Then he goes 1 Km towards west and reaches D. If he goes 2Km towards South, Where would he reach? Draw a Diagram and Justify it. Also find out the total distance he travelled. Journey diagram
He would reach A.
Total distance he travelled = (1 + 2 + 1 + 2)km = 6 km.
c. Sangeetha has just finished building a new house with garden area. She measured the garden area and found it to be 6m × 6m. Suppose she has to put a pole every 1m, how many poles are required? Each pole is of height 1.5m from the ground. What should be the total length of the fencing material to fence the garden?
Garden side a = 6m
Perimeter of the Garden = 4 × 6m = 24m
Poles are put every 1m except the 4 corners.
Required poles = (24−4) = 20
Height of each pole = 1.5m
Height of 20 poles = 20 × 1.5m = 30m
d. One student needs 1m 25 cm cloth to stitch a shirt. What is the total length of cloth need to stitch 22 shirts?
Length of cloth needed for 1 shirts = 1 m 25cm
Length of cloth needed for 22 shirts =
Cloth calculation Length of cloth needed for 22 shirts = 27m 50cm.
e. The distance from village A to village B is 3 km 450 m. The distance from village B to village C 5 km 350 m. How long will be the road laid from village A to village C?
The distance from village A to village B = 3 Km 450 m
The distance from village B to village C = 5 Km 350 m
The distance between village A to village C = [3 Km 450 m] + [5 Km 350 m] = 8 Km 800 m
The length of the road laid from village A to village C = 8km 800m

8. Create the story problem using the pictures given below:

Story Problem Objects
a) A student needs 2m 50cm cloth to stitch a skirt. What is the total length of cloth needed to stitch 35 skirts.
Length of cloth needed for 1 skirt = 2m 50cm
Length of cloth needed for 35 skirts =
Skirt calculation Length of cloth needed for 35 skirts = 87m 50 cm
b) The length of 225 m 75 cm rubber tube was cut into 25 pieces. What is the length of each piece?
The length of 25 pieces of rubber tube = 225m 75cm
The length of each piece of rubber tube = 225m 75 cm ÷ 25
Tube calculation The length of each piece of rubber tube = 9 m 03 cm
c) A carpenter cuts a long wood into 65 pieces. The length of each wooden piece is 3 m 45 cm. What is the length of the original long wood?
The length of each wooden piece = 3m 45cm
The length of 65 wooden pieces =
Wood calculation The length of original long wood = 224 m 25cm.
d) A factory produced 4515 water pipes. It was distributed equally to 7 shops. How many water pipes were distributed to each shop.
Water pipes distributed to 7 shops = 4515
Water pipes distributed to 1 shop = 4515 ÷ 7
Pipe distribution calculation Water pipes distributed to each shop = 645
Answer Key (Exercise: 4.1)
1. a) 705 cm b) 50 cm 5 mm c) 32600 cm d) 5300 m e) 6m 50 m
2. a) false b) true c) false d) true e) false
3. a) 69 m 750 cm b) 165 km 450 m c) 10 cm 7 mm
4. a) 2 km 250 m b) 380 m 360 mm c) 2 km 50 m
5. a) 2453 m 15 cm b)151 km 800 m c) 298 m 800 mm
6. a) 190 km 160 m b) 7m 110 mm c) 43m 12cm
7. a) 000322 b) 6 km c) 20 poles, 30 m d) 27 m 50 cm e)8 km 800 m