Exercise 1.4: Questions with Answers & Solution
Chapter: 6th Maths : Term 1 Unit 1 : Numbers
1. Fill in the blanks.
Answer: 800
Answer: 1000
Answer: 90000
2. Say True or False.
Answer: False
Answer: True
Answer: False
3. Round off the following to the given nearest place.
Compare tenth place 6 > 5; Add ‘1’ to hundredth place and make tenth and oneth place as zero.
4,065; hundred = \( 6 > 5 \)
= 4100
→ 45,000
→ 90,000
→ 51,00,000
→ 30,00,00,000
4. Estimate the sum
Estimate the sum of 157826 and 32469 rounded off to the nearest ten thousand.
Sum of 157826 and 32469
Actual:
157826 + 32469 = 1,90,295
Estimated sum = 1,60,000
nearest ten thousand = 30,000
Hence Estimated sum of 157826 and 32469 = 1,90,000
5. Estimate by rounding off each number to the nearest hundred.
nearest hundred = 8100 + 4200
= 12,300
Hence estimated of 8074 + 4178 = 12,300
nearest hundred = 1768977 + 130589
= 1899600
Hence estimated of 1768977 + 130589 = 1899600
6. Word Problem
The population of a city was 43,43,645 in the year 2001 and 46,81,087 in the year 2011. Estimate the increase in population by rounding off to the nearest thousand.
Population of city in 2001 = 43,43,645
in 2011 = 46,81,087
Estimate increase in population nearest to thousand is
Increase in population between 2011 to 2001 is 3,37,000
Objective Type Questions
7. The number which on rounding off to the nearest thousand gives 11000 is
Answer: (b) 108558. The estimation to the nearest hundred of 76812 is
Answer: (c) 768009. The number 9785764 is rounded off to the nearest lakh as
Answer: (a) 980000010. The estimated difference of 167826 and 2765 rounded off to the nearest thousand is
Answer: (b) 165000Answer Key Recap: Exercise 1.4
- 1) (i) 800 (ii) 1000 (iii) 90,000
- 2) (i) False (ii) True (iii) False
- 3) (i) 4100 (ii) 45,000 (iii) 90,000 (iv) 51,00,000 (v) 30,00,00,000
- 4) 1,90,000
- 5) (i) 12,300 (ii) 18,99,600
- 6) 3,37,000
- 7) (b) 10855
- 8) (c) 76800
- 9) (a) 9800000
- 10) (b) 165000