6th Maths Term 1 Unit 1 Numbers Exercise 1.5 Questions and Answers

6th Maths: Term 1 Unit 1 : Numbers

Exercise 1.5 Questions with Answers & Solutions

1. Fill in the blanks
(i) The difference between the smallest natural number and the smallest whole number is __________. Answer: one
(ii) 17 × __________ = 34 × 17 Answer: 34
(iii) When __________ is added to a number, it remains the same. Answer: zero
(iv) Division by __________ is not defined. Answer: zero
(v) Multiplication by __________ leaves a number unchanged. Answer: one
2. Say True or False
(i) 0 is the identity for multiplication of whole numbers. [False]
(ii) Sum of two whole numbers is always less than their product. [False]
(iii) Both addition and multiplication are associative for whole numbers. [True]
(iv) Both addition and multiplication are commutative for whole numbers. [True]
(v) Multiplication is distributive over addition for whole numbers. [True]
3. Properties Illustrated
(i) 75 + 34 = 34 + 75
→ Commutativity for addition
(ii) (12 × 4) × 8 = 12 × (4 × 8)
→ Associativity for multiplication
(iii) 50 + 0 = 50
→ Zero is Additive Identity
(iv) 50 × 1 = 50
→ One is Multiplicative Identity
(v) 50 × 42 = 50 × 40 + 50 × 2
→ Distributivity of multiplication over addition
4. Simplify using Properties
(i) 50 × 102
= 50 × (100 + 2)
= (50 × 100) + (50 × 2)
= 5000 + 100 = 5100
(ii) 500 × 689 − 500 × 89
= 500 (689 − 89)
= 500 × 600
= 3,00,000
(iii) 4 × 132 × 25
= 132 × (25 × 4)
= 132 × 100 = 13,200
(iv) 196 + 34 + 104
= (196 + 4) + 100 + 34
= 200 + 100 + 34
= 334
Objective Type Questions
5. (53 + 49) × 0 is (a) 102 (b) 0 (c) 1 (d) 53 + 49 × 0
6. 59/1 is (a) 1 (b) 0 (c) 1/59 (d) 59
7. The product of a non-zero whole number and its successor is always (a) an even number (b) an odd number (c) zero (d) none of these
8. The whole number that does not have a predecessor is (a) 10 (b) 0 (c) 1 (d) none of these
9. Which of the following expressions is not zero? (a) 0 × 0 (b) 0 + 0 (c) 2 / 0 (d) 0 / 2
10. Which of the following is not true? (a) (4237 + 5498) + 3439 = 4237 + (5498 + 3439) (b) (4237 × 5498) × 3439= 4237 × (5498 × 3439) (c) 4237 + 5498 × 3439 = (4237 + 5498) × 3439 (d) 4237 × (5498 + 3439) = (4237 × 5498) + (4237 × 3439)
Summary Answer Key: Exercise 1.5
Q.No Answer
1(i) 1 (ii) 34 (iii) 0 (iv) Zero (v) one
2(i) False (ii) False (iii) True (iv) True (v) True
3(i) Commutativity (ii) Associativity (iii) Additive Identity (iv) Multiplicative Identity (v) Distributivity
4(i) 5100 (ii) 3,00,000 (iii) 13,200 (iv) 334
5(b) 0
6(d) 59
7(a) an even number
8(b) 0
9(c) 2/0
10(c) 4237 + 5498 × 3439 = (4237 + 5498) × 3439